Question

which value of x makes this equation true? -4(3 - x) + 2x = 8 a. 20 b. -2/3 c. 10/3 d. -4

Explanation:

Step1: Expand the left side

$-4(3 - x) + 2x = -12 + 4x + 2x$

Step2: Combine like terms

$-12 + 6x = 8$

Step3: Isolate the x term

$6x = 8 + 12 = 20$

Step4: Solve for x

$x = \frac{20}{6} = \frac{10}{3}$

Answer:

C. $\frac{10}{3}$