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Question
while flipping a weighted coin, latrell gets 4 heads and 2 tails. based on experimental probability, how many of the next 3 flips should latrell expect to come up heads? heads
Step1: Calculate experimental - probability of heads
The total number of flips is $4 + 2=6$. The experimental - probability of getting a head, $P(H)=\frac{4}{6}=\frac{2}{3}$.
Step2: Calculate expected number of heads in 3 flips
The expected number of heads in $n = 3$ flips is $E=n\times P(H)$. Substitute $n = 3$ and $P(H)=\frac{2}{3}$ into the formula, we get $E = 3\times\frac{2}{3}=2$.
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