Question

a worker drops his hammer off the roof of a house. the hammer has a mass of 250g. gravity accelerates objects on earth at 9.8 m/s². how much force does the earth apply to the hammer?

Explanation:

Step1: Recall Newton's second - law

The formula for Newton's second - law is $F = ma$, where $F$ is the force, $m$ is the mass, and $a$ is the acceleration.

Step2: Identify given values

The mass of the hammer $m = 2.50\ kg$ and the acceleration due to gravity $a = g=9.8\ m/s^{2}$.

Step3: Calculate the force

Substitute the values into the formula $F = ma$. So $F=(2.50\ kg)\times(9.8\ m/s^{2}) = 24.5\ N$.

Answer:

$24.5\ N$