Question

write the balanced dissociation equation for solid iron(iii) nitrate in aqueous solution. if it does not dissociate, simply write only nr. be sure to include the proper phases for all species within the reaction.

Explanation:

Step1: Identify reactant and products

Iron(III) nitrate ($Fe(NO_3)_3$) in solid phase dissociates in water. The products are iron(III) ion ($Fe^{3 +}$) and nitrate ion ($NO_3^-$).
$Fe(NO_3)_3(s)\to Fe^{3+}(aq)+NO_3^-(aq)$

Step2: Balance the equation

There are 3 nitrate ions in $Fe(NO_3)_3$. So we need 3 moles of $NO_3^-$ on the product - side.
$Fe(NO_3)_3(s)\to Fe^{3+}(aq)+3NO_3^-(aq)$

Answer:

$Fe(NO_3)_3(s)\to Fe^{3+}(aq)+3NO_3^-(aq)$