Question

write the coordinates of the vertices after a reflection over the y - axis.
q(\square,\square)
r(\square,\square)
s(\square,\square)

Explanation:

Step1: Find original coordinates

First, identify the original coordinates of points \( Q \), \( R \), and \( S \) from the graph.

• For \( Q \): Looking at the graph, \( Q \) is at \( (-9, -6) \) (since it's 9 units left on the x - axis and 6 units down on the y - axis).
• For \( R \): \( R \) is at \( (-9, -1) \) (9 units left on the x - axis and 1 unit down on the y - axis).
• For \( S \): \( S \) is at \( (-4, -4) \) (4 units left on the x - axis and 4 units down on the y - axis).

Step2: Apply reflection over y - axis

The rule for reflecting a point \( (x,y) \) over the \( y \) - axis is \( (x,y)\to(-x,y) \).

• For \( Q(-9, -6) \):

Applying the rule, \( x=-9\), so \( -x = 9 \). The reflected point \( Q' \) is \( (9, -6) \).

• For \( R(-9, -1) \):

Applying the rule, \( x = - 9\), so \( -x=9 \). The reflected point \( R' \) is \( (9, -1) \).

• For \( S(-4, -4) \):

Applying the rule, \( x=-4\), so \( -x = 4 \). The reflected point \( S' \) is \( (4, -4) \).

Answer:

\( Q'(9, -6) \)
\( R'(9, -1) \)
\( S'(4, -4) \)