Question

write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: ca$^{2 +}$, ni$^{4+}$, br$^{-}$, o$^{2 -}$

Explanation:

Step1: Combine $Ca^{2 +}$ and $Br^{-}$

The charges must balance. For $Ca^{2+}$ and $Br^{-}$, we need 2 $Br^{-}$ for each $Ca^{2+}$. So the formula is $CaBr_{2}$.

Step2: Combine $Ca^{2 +}$ and $O^{2-}$

The charges of $Ca^{2+}$ and $O^{2 -}$ balance in a 1:1 ratio. The formula is $CaO$.

Step3: Combine $Ni^{4+}$ and $Br^{-}$

To balance the + 4 charge of $Ni^{4+}$, we need 4 $Br^{-}$. The formula is $NiBr_{4}$.

Step4: Combine $Ni^{4+}$ and $O^{2-}$

For the + 4 charge of $Ni^{4+}$ and - 2 charge of $O^{2-}$, we need 2 $O^{2-}$ for each $Ni^{4+}$. The formula is $NiO_{2}$.

Answer:

$CaBr_{2}$, $CaO$, $NiBr_{4}$, $NiO_{2}$