QUESTION IMAGE
Question
- write an equation in slope - intercept form for each line at the right.
b. what is the equation (5y + 22 = 5x - 33) written in slope intercept form?
a (y = x - 11)
b (y = 5x - 55)
c (5x = 5y + 55)
d (x = y + 11)
38 2 - 9 linear equations: (y = mx + b)
Step1: Start with the given equation
We have the equation \(5y + 22=5x - 33\). Our goal is to solve for \(y\) to get it in slope - intercept form \(y = mx + b\). First, we need to isolate the term with \(y\) on one side. Subtract 22 from both sides of the equation.
\(5y+22 - 22=5x - 33 - 22\)
Simplifying the left - hand side (LHS) and the right - hand side (RHS), we get \(5y=5x-(33 + 22)\) (because \(-33-22=-(33 + 22)\))
\(5y = 5x-55\)
Step2: Solve for y
Now, divide each term in the equation \(5y = 5x-55\) by 5 to solve for \(y\).
\(\frac{5y}{5}=\frac{5x}{5}-\frac{55}{5}\)
Simplifying each term, we know that \(\frac{5y}{5}=y\), \(\frac{5x}{5}=x\) and \(\frac{55}{5} = 11\). So the equation becomes \(y=x - 11\)
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A. \(y = x-11\)