Question

write the following in simplified radical fo sqrt5{96}

Explanation:

Step1: Factor 96 into prime factors

$96 = 32 \times 3 = 2^5 \times 3$

Step2: Separate 5th power factor

$\sqrt[5]{2^5 \times 3} = \sqrt[5]{2^5} \times \sqrt[5]{3}$

Step3: Simplify the 5th root

$\sqrt[5]{2^5} = 2$, so $2 \times \sqrt[5]{3}$

Answer:

$2\sqrt[5]{3}$