Question

a written description of a system of linear equations is given.
the first linear equation has a slope of 4 and a y-intercept of $-7$. the second linear equation has a slope of $-4$ and passes through the point $(-1, -2)$.
write the system of equations.
$y = 4x + 7$
$y + 2 = -4(x - 1)$
$y = 4x - 7$
$y + 2 = -4(x + 1)$
$y = 4x + 7$
$y - 2 = -4(x - 1)$
$y = 4x - 7$
$y + 2 = 4(x - 1)$

Explanation:

Step1: Write first equation (slope-intercept)

Slope-intercept form is $y=mx+b$, where $m=4$, $b=-7$.
$y=4x-7$

Step2: Write second equation (point-slope)

Point-slope form is $y-y_1=m(x-x_1)$, where $m=-4$, $(x_1,y_1)=(-1,-2)$.
$y-(-2)=-4(x-(-1))$ simplifies to $y+2=-4(x+1)$

Answer:

B. $y = 4x - 7$
$y + 2 = -4(x + 1)$