Question

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$g(x) = \

$$\begin{cases} -343x &, \\ x = -2 \\\\ (x - 1)(x + 2) &, \\ x = -1 \\\\ x^3 - x^2 + 1 &, \\ x \ eq -2, -1 \\end{cases}$$

$
$g(1) = \square$
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worked example: evaluating piecewise functions

Explanation:

Step1: Identify correct function piece

Since $1
eq -2,-1$, use $g(x)=x^3 - x^2 + 1$.

Step2: Substitute $x=1$ into the function

$g(1) = 1^3 - 1^2 + 1$

Step3: Calculate the result

$g(1)=1 - 1 + 1$

Answer:

$1$