Question

a 2.00 - meter stick is located in a uniform electric field of magnitude 400 v/m. the stick is oriented along the field so that the field points from the 0.00 cm mark to the 200.0 cm mark. the potential difference, δv = v(200.0 cm) - v(0.00 cm), is equal to

Explanation:

Step1: Recall the formula for potential difference

The formula for potential difference in a uniform electric - field is $\Delta V=-Ed$, where $E$ is the electric - field magnitude and $d$ is the displacement along the direction of the electric field.

Step2: Identify the values of $E$ and $d$

The electric - field magnitude $E = 400\ V/m$, and the displacement $d=(200.0 - 0.00)\ cm=2.00\ m$.

Step3: Calculate the potential difference

Substitute the values into the formula: $\Delta V=-Ed$. So, $\Delta V=-400\ V/m\times2.00\ m=-800\ V$.

Answer:

$- 800$