Question

a 0.075 kg bullet travels through the barrel of a gun, accelerating at 440 000 m/s², before leaving the barrel. what was the force of launch?
a meteorite accelerates towards a space station at 0.05 m/s² from an applied force of 300 n. what is the mass of the meteorite?
a 0.600 kg dynamics trolley has a 1.5 kg load added. it is launched with a force of 10 n. what is the acceleration?

Explanation:

Step1: Recall Newton's second - law

$F = ma$

Step2: Solve for the first problem (bullet)

Given $m = 0.075\ kg$ and $a=440000\ m/s^{2}$. Substitute into $F = ma$.
$F_1=0.075\times440000 = 33000\ N$

Step3: Solve for the second problem (meteorite)

Given $F = 300\ N$ and $a = 0.05\ m/s^{2}$. From $F = ma$, we can find $m$. So $m_2=\frac{F}{a}=\frac{300}{0.05}=6000\ kg$

Step4: Solve for the third problem (dynamics trolley)

First, find the total mass $m_3=0.600 + 1.5=2.1\ kg$. Given $F = 10\ N$. From $F = ma$, we can find $a$. So $a_3=\frac{F}{m_3}=\frac{10}{2.1}\approx4.76\ m/s^{2}$

Answer:

1. Force of launch for bullet: $33000\ N$
2. Mass of meteorite: $6000\ kg$
3. Acceleration of trolley: $4.76\ m/s^{2}$