Question

10
10 cm.
11 cm.
8 cm.
16 cm.
11
17 cm.
38 cm
26 cm.
494

Explanation:

Step1: Identify trapezoid area formula

The area of a trapezoid is given by $\text{Area} = \frac{1}{2} \times (a + b) \times h$, where $a$ and $b$ are the lengths of the two parallel sides, and $h$ is the height.

Step2: Substitute values for trapezoid (Q10)

For the trapezoid, $a = 10\ \text{cm}$, $b = 16\ \text{cm}$, $h = 8\ \text{cm}$.
$\text{Area} = \frac{1}{2} \times (10 + 16) \times 8$
First calculate the sum inside the parentheses: $10 + 16 = 26$
Then compute $\frac{1}{2} \times 26 \times 8 = 13 \times 8 = 104$

Step3: Identify kite area formula

The area of a kite is $\text{Area} = \frac{1}{2} \times d_1 \times d_2$, where $d_1$ and $d_2$ are the lengths of the diagonals.

Step4: Substitute values for kite (Q11)

For the kite, $d_1 = 26\ \text{cm}$, $d_2 = 38\ \text{cm}$.
$\text{Area} = \frac{1}{2} \times 26 \times 38$
First calculate $26 \times 38 = 988$, then $\frac{1}{2} \times 988 = 494$

Answer:

1. Area of figure 10: $104\ \text{cm}^2$
2. Area of figure 11: $494\ \text{cm}^2$