Question

y ( 6\frac{1}{2} - 1\frac{9}{10} )
i ( \frac{2}{5} ) of 40
b ( 2\frac{5}{8} \times \frac{4}{7} \times 12 )
o ( 4\frac{2}{3} div 10 )

Explanation:

Step1: Convert mixed numbers to improper fractions

For Y: $6\frac{1}{2} = \frac{13}{2}$, $1\frac{9}{10} = \frac{19}{10}$
For B: $2\frac{5}{8} = \frac{21}{8}$
For O: $4\frac{2}{3} = \frac{14}{3}$

Step2: Solve Y (subtract fractions)

Find common denominator (10):
$\frac{13}{2} = \frac{65}{10}$
$\frac{65}{10} - \frac{19}{10} = \frac{65-19}{10} = \frac{46}{10} = \frac{23}{5}$

Step3: Solve I (fraction of whole number)

"Of" means multiplication:
$\frac{2}{5} \times 40 = \frac{2 \times 40}{5} = 16$

Step4: Solve B (multiply fractions/numbers)

Simplify and multiply step-by-step:
$\frac{21}{8} \times \frac{4}{7} = \frac{21 \times 4}{8 \times 7} = \frac{3}{2}$
$\frac{3}{2} \times 12 = \frac{3 \times 12}{2} = 18$

Step5: Solve O (divide fraction by whole number)

Rewrite division as multiplication by reciprocal:
$\frac{14}{3} \div 10 = \frac{14}{3} \times \frac{1}{10} = \frac{14}{30} = \frac{7}{15}$

Answer:

Y: $\frac{23}{5}$ or $4\frac{3}{5}$
I: $16$
B: $18$
O: $\frac{7}{15}$