Question

10 bullfrogs from a pond are randomly selected. a mean jump length of 7.58 feet is calculated with a margin of error of ±0.52 for a 90% confidence interval. what is the interval estimate of the population mean? a 7.06 < μ < 8.10 b 7.06 > μ > 8.10 c 7.09 < μ < 2.07 d 7.09 > μ > 2.07 e 7.20 < μ < 8.10

Explanation:

Step1: Calculate lower - bound

Subtract margin of error from sample mean.
$7.58 - 0.52=7.06$

Step2: Calculate upper - bound

Add margin of error to sample mean.
$7.58 + 0.52 = 8.10$

Answer:

A. $7.06<\mu<8.10$