Question

1. calculate the ph of a solution that is 0.153 m hcl. √3

Explanation:

Step1: Identify H⁺ concentration

HCl is a strong acid, so it dissociates completely: $\ce{HCl -> H^+ + Cl^-}$. Thus, $[\ce{H^+}] = 0.153\ \text{M}$.

Step2: Calculate pH using formula

Use the pH definition: $\text{pH} = -\log_{10}[\ce{H^+}]$
<Expression>
$\text{pH} = -\log_{10}(0.153)$
</Expression>

Step3: Compute the logarithmic value

Calculate the log value: $-\log_{10}(0.153) \approx 0.815$

Answer:

0.815