Question

1. if dh = 2x - 2 and fh = x + 6, find the value of x for which defg must be a parallelogram.

5
10
13
8

Explanation:

Step1: Recall parallelogram property

In a parallelogram, the diagonals bisect each other. So, $DH = FH$.

Step2: Set up the equation

Set $2x - 2=x + 6$.

Step3: Solve the equation

Subtract $x$ from both sides: $2x-x-2=x - x+ 6$, which simplifies to $x - 2=6$. Then add 2 to both sides: $x-2 + 2=6 + 2$, so $x = 8$.

Answer:

8