Question

1. find the area of the trapezoid.

4 mi
4 mi
5 mi
$a = \square$ $mi^2$
grade 6: mrl cc>chapter 7>practice test> question #4

Explanation:

planation:

Step1: Recall trapezoid area formula

The area formula for a trapezoid is $A = \frac{1}{2}(b_1 + b_2)h$, where $b_1$ and $b_2$ are the lengths of the two parallel sides, and $h$ is the height.

Step2: Identify given values

Here, $b_1 = 4$ mi, $b_2 = 5$ mi, $h = 4$ mi.

Step3: Substitute values into formula

$A = \frac{1}{2}(4 + 5) \times 4$

Step4: Calculate sum inside parentheses

$4 + 5 = 9$

Step5: Compute final area

$A = \frac{1}{2} \times 9 \times 4 = 18$

Answer:

18