QUESTION IMAGE
Question
- a glass cup that holds 8 ounces of liquid has a mass of 0.225 kg.
a. how much heat it would take to change the temperature of the glass by eight degrees celsius?
b. convert eight degrees celsius to kelvin.
- the average human body has a mass sixty kilograms.
a. calculate how much thermal energy is needed to raise the temperature 0.5 °c for an average.
b. convert 0.5 °c to fahrenheit.
Step1: Recall heat formula for glass
The heat required is calculated using $Q = mc\Delta T$, where $m=0.225\ \text{kg}$, $c=840\ \text{J/(kg·°C)}$ (specific heat of glass), $\Delta T=8\ \text{°C}$.
Step2: Substitute values and solve
$Q = 0.225 \times 840 \times 8$
$Q = 0.225 \times 6720 = 1512\ \text{J}$
Step3: Convert °C to Kelvin
Use $K = °C + 273.15$, $\Delta T_K = 8 + 273.15$
Step4: Recall heat formula for human body
Use $Q = mc\Delta T$, where $m=60\ \text{kg}$, $c=3500\ \text{J/(kg·°C)}$ (specific heat of human body), $\Delta T=0.5\ \text{°C}$.
Step5: Substitute values and solve
$Q = 60 \times 3500 \times 0.5$
$Q = 60 \times 1750 = 105000\ \text{J} = 1.05 \times 10^5\ \text{J}$
Step6: Convert °C to Fahrenheit
Use $°F = (°C \times \frac{9}{5}) + 32$, $°F = (0.5 \times \frac{9}{5}) + 32$
$°F = 0.9 + 32 = 32.9$
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10a. $1512\ \text{J}$
10b. $281.15\ \text{K}$
11a. $1.05 \times 10^5\ \text{J}$
11b. $32.9\ \text{°F}$