Question

if a 10.4 kg block is on a rough horizontal table with a coefficient of friction μ=0.15, then what is the resulting force of friction on the block?
___ n
use g=9.81 m/s² and do not include units in your answer.
enter the answer

Explanation:

Step1: Calculate normal force

The normal force $N$ on a horizontal surface for a block is equal to its weight. Weight $W = mg$, where $m = 10.4$ kg and $g=9.81$ m/s². So $N=mg = 10.4\times9.81$.

Step2: Calculate frictional force

The formula for frictional force $F_f=\mu N$. Substitute $\mu = 0.15$ and $N = 10.4\times9.81$ into the formula. $F_f=0.15\times10.4\times9.81$.
$F_f=0.15\times10.4\times9.81=15.2982\approx15.3$

Answer:

$15.3$