Question

1. a particle traveled a distance of $9.0 \times 10^{12}$ meters at a rate of $1.8 \times 10^5$ meters per second. if distance = rate $\times$ time, how many seconds did it take the particle to travel the specified distance?\

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a. $1.62 \times 10^{18}$ seconds\
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b. $1.08 \times 10^8$ seconds\
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c. $5 \times 10^7$ seconds\
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d. $2 \times 10^{-4}$ seconds

Explanation:

Step1: Rearrange formula for time

$time = \frac{distance}{rate}$

Step2: Substitute given values

$time = \frac{9.0 \times 10^{12}}{1.8 \times 10^{5}}$

Step3: Divide coefficients and exponents

$\frac{9.0}{1.8} = 5$, $\frac{10^{12}}{10^{5}} = 10^{12-5}=10^7$

Step4: Combine results

$time = 5 \times 10^7$

Answer:

C. $5 \times 10^{7}$ seconds