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10. a sealed container has a pressure of 1.5 atm at 25°c. if the temper…

Question

  1. a sealed container has a pressure of 1.5 atm at 25°c. if the temperature is raised to 125°c, what will be the new pressure?

o 2
o 7.5
o 1.12
o 0.3

  1. the relationship between volume and temperature is ____.

o direct
o inverse
o neither

Explanation:

Step1: Convert temperatures to Kelvin

For initial temperature $T_1 = 25^{\circ}C+ 273 = 298K$, for final temperature $T_2=125^{\circ}C + 273=398K$. Initial pressure $P_1 = 1.5atm$.

Step2: Apply Gay - Lussac's law ($\frac{P_1}{T_1}=\frac{P_2}{T_2}$)

We can solve for $P_2$, so $P_2=\frac{P_1T_2}{T_1}$. Substitute $P_1 = 1.5atm$, $T_1 = 298K$ and $T_2 = 398K$ into the formula: $P_2=\frac{1.5\times398}{298}\approx2atm$.

For the second question:

Brief Explanations

According to Charles's law, for a given amount of gas at constant pressure, the volume of a gas is directly proportional to its absolute temperature. So the relationship between volume and temperature is direct.

Answer:

  1. A. 2
  2. A. direct