Question

100.0 ml of a 0.500 m kbr solution is diluted to 500.0 ml. what is the new concentration of the solution?

Explanation:

Step1: Identify the dilution formula

The formula for dilution is $M_1V_1 = M_2V_2$, where $M_1$ is the initial molarity, $V_1$ is the initial volume, $M_2$ is the final molarity, and $V_2$ is the final volume.

Step2: Assign values to variables

$M_1=0.500\ M$, $V_1 = 100.0\ mL$, $V_2=500.0\ mL$. We need to find $M_2$.

Step3: Rearrange the formula to solve for $M_2$

$M_2=\frac{M_1V_1}{V_2}$

Step4: Substitute values into the rearranged formula

$M_2=\frac{0.500\ M\times100.0\ mL}{500.0\ mL}$
$M_2 = 0.100\ M$

Answer:

$0.100\ M$