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Question
- you have a gas in a container fitted with a piston and you change one of the conditions of the gas such that a change takes place, as shown below: 1.00 atm state two distinct changes you can make to accomplish this, and explain why each would work.
Brief Explanations
According to the ideal - gas law $PV = nRT$. The volume of the gas in the container has decreased. One change could be decreasing the temperature. From $V=\frac{nR}{P}T$ (at constant $n$ and $P$), a decrease in $T$ leads to a decrease in $V$. Another change could be increasing the external pressure. From $V=\frac{nRT}{P}$ (at constant $n$ and $T$), an increase in $P$ leads to a decrease in $V$.
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- Decrease the temperature: At constant pressure and amount of gas, volume is proportional to temperature according to Charles's law ($V\propto T$).
- Increase the external pressure: At constant temperature and amount of gas, volume is inversely proportional to pressure according to Boyle's law ($V\propto\frac{1}{P}$).