Question

11/23
factor $r^2 -16r + 60$
$(r - 15)(r + 4)$
$(r +30)(r - 2)$
$(r - 6)(r - 10)$
$(r - 6)(r + 10)$

Explanation:

Step1: Identify $a,b,c$ for quadratic

For $r^2-16r+60$, $a=1$, $b=-16$, $c=60$

Step2: Find pair with sum $b$, product $ac$

Need two numbers: sum $=-16$, product $=1\times60=60$. The numbers are $-10$ and $-6$.

Step3: Factor the quadratic

Rewrite middle term and factor:
$r^2-10r-6r+60 = r(r-10)-6(r-10)=(r-6)(r-10)$

Answer:

$(r - 6)(r - 10)$