Question

1. the average temperatures for two of the worlds coldest places are given. determine which location has the colder average temperature and by how many degrees celsius. round to the nearest tenth of a degree. location a: $-31.7^circ$c and location b: $-10.8^circ$f the location with the colder average temperature is (1) ________, which is colder by about $square^circ$c. (round to the nearest tenth of a degree.) (1) $\bigcirc$ location b $\bigcirc$ location a

Explanation:

Step1: Convert Fahrenheit to Celsius

The formula to convert Fahrenheit to Celsius is $C = \frac{5}{9}(F - 32)$. For Location B, $F=-10.8$. So we substitute into the formula:
$C=\frac{5}{9}(-10.8 - 32)=\frac{5}{9}(-42.8)\approx - 23.8^{\circ}C$

Step2: Compare temperatures

Location A: $-31.7^{\circ}C$, Location B: $\approx -23.8^{\circ}C$. Since $-31.7 < -23.8$, Location A is colder.

Step3: Find the difference

Subtract the temperature of Location B from Location A: $-31.7-(-23.8)=-31.7 + 23.8=-7.9^{\circ}C$ (the negative sign indicates Location A is colder by that amount, we take the absolute value for the degree of coldness difference).

Answer:

(1) Location A, which is colder by about $7.9^{\circ}C$.