Question

1. calculate the final temperature of water if the heat from combusting one entire pistachio goes into the container of water.

measurements you may find helpful:

• heat released by entire pistachio: student response j
• initial temperature of water: 20.0 °c
• mass of one pistachio: 0.511g
• mass of water in the container: 500 g

i need a hint
°c
the answer to this question depends on your answers to previous questions.
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Explanation:

Step1: Recall heat - transfer formula

The heat - transfer formula is $Q = mc\Delta T$, where $Q$ is the heat energy, $m$ is the mass, $c$ is the specific heat capacity, and $\Delta T=T_{final}-T_{initial}$. The specific heat capacity of water $c = 4.18\ J/(g\cdot^{\circ}C)$. We know $Q$ (heat released by pistachio), $m$ (mass of water), and $T_{initial}$. We can re - arrange the formula to solve for $T_{final}$: $T_{final}=T_{initial}+\frac{Q}{mc}$.

Step2: Substitute given values

We are given $T_{initial}=20.0^{\circ}C$, $m = 500\ g$, and $c = 4.18\ J/(g\cdot^{\circ}C)$. Let the heat released by the pistachio be $Q$ (Student Response J). Then $T_{final}=20.0+\frac{Q}{500\times4.18}$.

Answer:

$20.0+\frac{Q}{2090}$ (where $Q$ is the heat released by the entire pistachio)