Question

1. find the x - intercepts of the parabola with equation $y = x^2 - 9$.

options:
$9, -3$
$3, -3$
$9, 0$
$3, 9$

Explanation:

Step1: Set $y=0$ for x-intercepts

$0 = x^2 - 9$

Step2: Rearrange the equation

$x^2 = 9$

Step3: Solve for $x$

$x = \pm\sqrt{9} = \pm3$

Answer:

3, -3