Question

1. a high diver has a moment of inertia of $35\\ kg\cdot m^2$ and an angular velocity of $12\\ \frac{rad}{s}$. determine the divers angular momentum.\

$\bigcirc\\ 360\\ \frac{kg\cdot m^2}{s}$\
$\bigcirc\\ 420\\ \frac{kg\cdot m^2}{s}$\
$\bigcirc\\ 47\\ \frac{kg\cdot m^2}{s}$\
$\bigcirc\\ 480\\ \frac{kg\cdot m^2}{s}$

Explanation:

Step1: Recall angular momentum formula

Angular momentum $L = I\omega$

Step2: Substitute given values

$I=35\ \text{kg}\cdot\text{m}^2$, $\omega=12\ \frac{\text{rad}}{\text{s}}$
$L = 35 \times 12$

Step3: Calculate final value

$L = 420\ \frac{\text{kg}\cdot\text{m}^2}{\text{s}}$

Answer:

B. $420 \frac{\text{kg}\cdot\text{m}^2}{\text{s}}$