Question

1. a refrigerator that is 200 kg experiences an applied force to the right of 700 newtons. the force of friction is 600 newtons. calculate the acceleration of the refrigerator: 0.5 m/s² -0.5 m/s² 2 m/s² -2 m/s²

Explanation:

Step1: Identify net force

The applied force \( F_{applied} = 700\ N \) (right), friction \( F_{friction} = 600\ N \) (left). Net force \( F_{net}=F_{applied}-F_{friction}=700 - 600 = 100\ N \) (right).

Step2: Apply Newton's second law

Newton's second law: \( F_{net}=ma \), so \( a=\frac{F_{net}}{m} \). Mass \( m = 200\ kg \), \( F_{net}=100\ N \). Then \( a=\frac{100}{200}=0.5\ m/s^{2} \). Wait, no, wait—wait, maybe I messed up. Wait, no, wait: Wait, the applied force is right, friction is left. So net force is \( 700 - 600 = 100\ N \) right. Then \( a = F_{net}/m = 100/200 = 0.5\ m/s² \)? But wait, the options have 0.5, -0.5, 2, -2. Wait, maybe I got the direction wrong? Wait, no, the question says "applied force to the right", friction is opposite. Wait, maybe I made a mistake. Wait, let's recalculate: \( F_{net}=700 - 600 = 100\ N \). \( m = 200\ kg \). \( a = 100/200 = 0.5\ m/s² \). So the acceleration is \( 0.5\ m/s² \) to the right, so positive 0.5. Wait, but the options: first option is 0.5 m/s², second -0.5, third 2, fourth -2. Wait, maybe I messed up the forces. Wait, no—wait, maybe the applied force is 700, friction is 600, so net force is 100 N right. Then acceleration is 0.5 m/s². So the correct answer should be 0.5 m/s². Wait, but let me check again. \( F = ma \), so \( a = F/m \). Net force is 700 - 600 = 100 N. Mass 200 kg. So 100/200 = 0.5 m/s². So the answer is 0.5 m/s².

Wait, but the user's options: first option is 0.5 m/s², second -0.5, third 2, fourth -2. So the correct one is 0.5 m/s².

Answer:

0.5 m/s² (corresponding to the first option: 0.5 m/s²)