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11. solve for x. round to the nearest tenth, if necessary. (there is a …

Question

  1. solve for x. round to the nearest tenth, if necessary.

(there is a right triangle klm with right angle at l, hypotenuse km = 2.8, angle at m is 28 degrees, and side kl = x)

Explanation:

Step1: Identify trigonometric ratio

For $\angle M = 28^\circ$, side $x$ is opposite, and side $MK=2.8$ is hypotenuse. Use sine:
$\sin(28^\circ) = \frac{x}{2.8}$

Step2: Isolate $x$

Rearrange to solve for $x$:
$x = 2.8 \times \sin(28^\circ)$

Step3: Calculate value

Compute $\sin(28^\circ) \approx 0.4695$, then:
$x \approx 2.8 \times 0.4695$

Answer:

$x \approx 1.3$