Question

q.11 trigonometric ratios: find a side length
find wx.
write your answer as an integer or as a decimal rounded to the nearest tenth.
$wx = \square$
submit

Explanation:

Step1: Identify trigonometric ratio

In right $\triangle XYW$, $\angle Y=62^\circ$, opposite side to $\angle Y$ is $WX$, adjacent side is $XY=\sqrt{19}$. Use tangent:
$\tan(62^\circ) = \frac{WX}{XY}$

Step2: Rearrange to solve for WX

Isolate $WX$ by multiplying both sides by $XY$:
$WX = XY \times \tan(62^\circ)$

Step3: Substitute values and calculate

First, $\sqrt{19} \approx 4.3589$, $\tan(62^\circ) \approx 1.8807$
$WX \approx 4.3589 \times 1.8807 \approx 8.2$

Answer:

$8.2$