Question

1. what is the specific heat of a solid that requires 124 j of heat to raise the temperature of 95.5 g of the substance from 20.0°c to 25.0°c? (1pts)

heat = mass × specific heat × δt
where δt = t_final - t_initial
□ 2.6 j/g°c
□ 0.26 j/g°c
□ 1.4 j/g°c
□ 5.9 × 10⁴ j/g°c

Explanation:

Step1: Calculate temperature change

$\Delta t = t_{final} - t_{initial} = 25.0^\circ\text{C} - 20.0^\circ\text{C} = 5.0^\circ\text{C}$

Step2: Rearrange heat formula for specific heat

Specific heat $= \frac{\text{heat}}{\text{mass} \times \Delta t}$

Step3: Substitute values into formula

Specific heat $= \frac{124\ \text{J}}{95.5\ \text{g} \times 5.0^\circ\text{C}} = \frac{124}{477.5}\ \text{J/g}^\circ\text{C} \approx 0.26\ \text{J/g}^\circ\text{C}$

Answer:

0.26 J/g°C