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Question
110.ps - 15
the table shows the proportional relationship between a hedgehogs weight loss and the number of days of hibernation. how much weight does the hedgehog lose during 115 days of hibernation? use pencil and paper. explain how you know that the relationship between the hedgehogs weight loss and the number of days of hibernation is proportional.
weight loss of hedgehog
| days of hibernation | change in weight (oz) |
|---|---|
| 22 | -0.66 |
the hedgehogs total change in weight over 115 days is (square) ounces.
(type an integer or a decimal.)
enter your answer in the answer box and then click check answer.
Step1: Find the rate of weight - loss per day
The rate $r$ of weight - loss per day can be found using the formula $r=\frac{\text{Change in Weight}}{\text{Days of Hibernation}}$. Using the first row of the table where days $d_1 = 6$ and change in weight $w_1=- 0.18$, we have $r=\frac{-0.18}{6}=-0.03$ oz per day. We can double - check with the second row: when $d_2 = 22$ and $w_2=-0.66$, $r=\frac{-0.66}{22}=-0.03$ oz per day.
Step2: Calculate the weight - loss in 115 days
We know that the change in weight $w$ for $n = 115$ days is given by the formula $w=r\times n$. Substituting $r=-0.03$ and $n = 115$ into the formula, we get $w=-0.03\times115=-3.45$ oz.
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$-3.45$