Question

9/12
the radius of a fluorine atom is about $5 \times 10^{-8}$ millimeter. the radius of a strontium atom is about $2 \times 10^{-7}$ millimeter. about how many times larger is the radius of a strontium atom than the radius of a fluorine atom?
4 times larger
40 times larger

Explanation:

Step1: Set up division ratio

$\frac{\text{Strontium radius}}{\text{Fluorine radius}} = \frac{2 \times 10^{-7}}{5 \times 10^{-8}}$

Step2: Split into coefficient & power

$\frac{2}{5} \times \frac{10^{-7}}{10^{-8}}$

Step3: Simplify coefficient and powers

$0.4 \times 10^{(-7)-(-8)} = 0.4 \times 10^{1}$

Step4: Final calculation

$0.4 \times 10 = 4$

Answer:

4 times larger