Question

1. (2.04 mc) a shipment of racquetballs with a mean diameter of 60 mm and a standard deviation of 0.9 mm is normally distributed. by how many standard deviations does a racquetball with a diameter of 58.2 mm differ from the mean? (5 points)

Explanation:

Step1: Calculate deviation from mean

$58.2 - 60 = -1.8$

Step2: Divide by standard deviation

$\frac{-1.8}{0.9} = -2$
(The negative sign indicates it is below the mean; we care about the magnitude of standard deviations.)

Answer:

2