Question

1. a 5 n force is applied to a 3 kg ball to change its velocity from +9 m/s to +3 m/s. the impulse on the ball is ______ n.s. impulse = force x time i = mass x (velocity final - velocity initial)

Explanation:

Step1: Identify the formula

We use the formula $I = m(v_f - v_i)$, where $I$ is impulse, $m$ is mass, $v_f$ is final - velocity and $v_i$ is initial - velocity.

Step2: Substitute the values

Given $m = 3\ kg$, $v_f=3\ m/s$, $v_i = 9\ m/s$. Then $I=3\times(3 - 9)$.

Step3: Calculate the result

$I=3\times(- 6)=-18\ N\cdot s$. The magnitude of the impulse is $18\ N\cdot s$.

Answer:

$18$