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13. what is the value of x to the nearest tenth? ○ 26.8 ○ 30.0

Question

13.
what is the value of x to the nearest tenth?
○ 26.8
○ 30.0

Explanation:

Step1: Identify the right triangle

We have a right triangle with hypotenuse 18 (radius of the circle) and one leg 12. Let the other leg (half of the chord) be \( y \). Using the Pythagorean theorem \( a^2 + b^2 = c^2 \), where \( c = 18 \) and \( b = 12 \), we solve for \( y \).
\[
y^2 + 12^2 = 18^2
\]
\[
y^2 + 144 = 324
\]
\[
y^2 = 324 - 144
\]
\[
y^2 = 180
\]
\[
y = \sqrt{180}
\]

Step2: Find the length of the chord \( x \)

Since the perpendicular from the center to a chord bisects the chord, \( x = 2y \).
\[
x = 2\sqrt{180}
\]
\[
x = 2\times13.4164
\]
\[
x \approx 26.8
\]

Answer:

26.8