Question

1. 130 - 15x = 10
2. 63 - 5x = 28

Explanation:

Problem 9: \( 130 - 15x = 10 \)

Step 1: Subtract 130 from both sides

To isolate the term with \( x \), we subtract 130 from both sides of the equation.
\( 130 - 15x - 130 = 10 - 130 \)
\( -15x = -120 \)

Step 2: Divide both sides by -15

To solve for \( x \), we divide both sides of the equation by -15.
\( \frac{-15x}{-15} = \frac{-120}{-15} \)
\( x = 8 \)

Step 1: Subtract 63 from both sides

To isolate the term with \( x \), we subtract 63 from both sides of the equation.
\( 63 - 5x - 63 = 28 - 63 \)
\( -5x = -35 \)

Step 2: Divide both sides by -5

To solve for \( x \), we divide both sides of the equation by -5.
\( \frac{-5x}{-5} = \frac{-35}{-5} \)
\( x = 7 \)

Answer:

\( x = 8 \)

Problem 11: \( 63 - 5x = 28 \)