Question

1. a 6kg cart accelerates at 9 m/s² for 2 m. how much work is done?
2. a machine does 840 j of work over 14 m. what force was used?

Explanation:

Question 14:

Step1: Find the force using \( F = ma \)

Given mass \( m = 6 \, \text{kg} \) and acceleration \( a = 9 \, \text{m/s}^2 \), so \( F = 6 \times 9 = 54 \, \text{N} \).

Step2: Calculate work using \( W = Fd \)

Distance \( d = 2 \, \text{m} \), so \( W = 54 \times 2 = 108 \, \text{J} \).

Step1: Rearrange work formula for force

From \( W = Fd \), we get \( F = \frac{W}{d} \).

Step2: Substitute values

Given \( W = 840 \, \text{J} \) and \( d = 14 \, \text{m} \), so \( F = \frac{840}{14} = 60 \, \text{N} \).

Answer:

\( 108 \, \text{J} \)

Question 15: