QUESTION IMAGE
Question
- emission increases the stability of the nucleus
- not deflected by any magnetic or electrical fields
- write the nuclear decay equation for thorium - 230 undergoing alpha decay
$_{90}^{230}th\
ightarrow_{88}^{226}ra + _{2}^{4}he$
- write the nuclear decay equation for $_{3}^{8}li$ emitting a beta particle
$_{3}^{8}li\
ightarrow_{4}^{7}be+_{ - 1}^{0}e$
- thorium - 234 can undergo beta particle production. what is the other product?
Step1: Recall beta - decay rule
In beta - decay, a neutron in the nucleus changes to a proton and an electron (beta particle). The atomic number increases by 1 and the mass number remains the same.
Step2: Write the decay equation for Th - 234
$^{234}_{90}Th
ightarrow^{234}_{91}Pa + _{- 1}^0e$
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$^{234}_{91}Pa$