Question

1. an irregular metal piece: water before = 45 ml, water after = 51.2 ml.

volume = ______ ml

1. a shell is placed in water: water before = 20 ml, water after = 26.3 ml.

volume = ______ ml
part d: density

1. a cube has mass = 36 g, volume = 9 cm³.

density = ______ g/cm³

1. a cylinder has mass = 80 g, volume = 40 cm³.

density = ______ g/cm³

1. a small block has mass = 50 g, volume = 25 cm³.

density = ______ g/cm³

1. a metal piece has mass = 120 g, volume = 30 cm³.

density = ______ g/cm³

1. a mixed material cylinder:

• material a: mass = 30 g, volume = 10 cm³
• material b: mass = 20 g, volume = 5 cm³

a) total mass = ______ g
b) total volume = ______ cm³
c) overall density = ______ g/cm³
d) will it float in water? explain: ______

Explanation:

Question 14

Step1: Find volume of metal piece

The volume of the irregular metal piece is the difference between the water level after and before placing the metal piece. So, we subtract the initial volume from the final volume.
\[ \text{Volume} = 51.2 - 45 \]

Step2: Calculate the result

\[ 51.2 - 45 = 6.2 \]

Step1: Find volume of shell

The volume of the shell is the difference between the water level after and before placing the shell. Subtract the initial volume from the final volume.
\[ \text{Volume} = 26.3 - 20 \]

Step2: Calculate the result

\[ 26.3 - 20 = 6.3 \]

Step1: Recall density formula

The formula for density (\(
ho \)) is \(
ho=\frac{\text{mass}}{\text{volume}} \). Here, mass is \( 36 \, \text{g} \) and volume is \( 9 \, \text{cm}^3 \).
\[
ho=\frac{36}{9} \]

Step2: Calculate density

\[ \frac{36}{9} = 4 \]

Answer:

\( 6.2 \)

Question 15