Question

1. suppose a 0.170kg hockey puck is at rest on the ice and a player shoots a slapshot giving the puck a speed of $35.76\frac{m}{s}$. how much work did the hockey stick do on the puck?\

\bigcirc\\ 217.4j\
\bigcirc\\ 108.7j\
\bigcirc\\ 0.1j\
\bigcirc\\ 2j

Explanation:

Step1: Recall Work-Energy Theorem

Work done = Change in KE

Step2: Define initial/final KE

Initial KE: $KE_i = 0$ (puck at rest)
Final KE: $KE_f = \frac{1}{2}mv^2$

Step3: Substitute given values

$m=0.170\ \text{kg}$, $v=35.76\ \text{m/s}$
$KE_f = \frac{1}{2} \times 0.170 \times (35.76)^2$

Step4: Calculate final value

$\frac{1}{2} \times 0.170 \times 1280.7776 = 108.866\ \text{J} \approx 108.7\ \text{J}$

Answer:

108.7J