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Question
- $g = b + \frac{m}{a}$, for $a$
- $g = x - c + y$, for $x$
- $g = b - ca$, for $a$
- $g = ca - b$, for $a$
- $2x + 4 = xg$, for $x$
- $g = \frac{1 + 2a}{a}$, for $a$
- $g = \frac{x - c}{x}$, for $x$
- $xm = x + z$, for $x$
- $u + ka = ba$, for $a$
- $u = kx + yx$, for $x$
- $u = 3b - 2a + 2$, for $a$
- $z = 9a - 9 - 3b$, for $a$
- $g = 4ca - 3ba$, for $a$
- $-3a - 3 = -2n + 3p$, for $a$
- $4x = -4r + 2d$, for $x$
- $u = \frac{-2a - 3}{ka}$, for $a$
Let's solve problem 29: \( 4x = -4r + 2d \), for \( x \)
Step 1: Isolate \( x \)
To solve for \( x \), we need to divide both sides of the equation by the coefficient of \( x \), which is 4.
\[
\frac{4x}{4} = \frac{-4r + 2d}{4}
\]
Step 2: Simplify both sides
Simplify the left side: \( \frac{4x}{4} = x \)
Simplify the right side: We can factor out a 2 from the numerator: \( \frac{2(-2r + d)}{4} \), then simplify the fraction by dividing numerator and denominator by 2: \( \frac{-2r + d}{2} \) or we can split the fraction: \( \frac{-4r}{4} + \frac{2d}{4} = -r + \frac{d}{2} \)
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\( x = -r + \frac{d}{2} \) (or \( x = \frac{-2r + d}{2} \))