Question

1. the coordinates of △pqr and its image are shown. describe the transformation. p(-6, 0)→p(-6, 0) q(2, -4)→q(2, 4) r(-7, 5)→r(-7, -5)

Explanation:

Step1: Analyze y - coordinate changes

For point $P(-6,0)\to P'(-6,0)$, the y - coordinate remains the same. For $Q(2, - 4)\to Q'(2,4)$, the y - coordinate changes from $-4$ to $4$ (multiplied by $- 1$). For $R(-7,5)\to R'(-7,-5)$, the y - coordinate changes from $5$ to $-5$ (multiplied by $-1$). The x - coordinates of all points remain unchanged.

Step2: Identify the transformation

When the x - coordinates of all points in a figure remain the same and the y - coordinates are multiplied by $-1$, the transformation is a reflection over the x - axis.

Answer:

The transformation is a reflection over the x - axis.