Question

1. if the green team pulls with 50 n and 70 n of force, and the red team pulls with 90 n and 25 n of force, what is the net force on the rope. clear all 5 n left 120 n left 115 n right 235 n right

Explanation:

Step1: Calculate total force by green team

The green team's total force is the sum of the two - forces they apply. So, $F_{green}=50 + 70=120$ N.

Step2: Calculate total force by red team

The red team's total force is the sum of the two - forces they apply. So, $F_{red}=90 + 25 = 115$ N.

Step3: Calculate net force

Assume the direction of the green - team's pull as positive. The net force $F_{net}=F_{green}-F_{red}$. Substitute the values: $F_{net}=120 - 115=5$ N. Since the result is positive, the net force is 5 N in the direction of the green team's pull (left - hand side as per the problem context).

Answer:

5 N Left