Question

1. using the punnett square below, determine the percent chances of the offspring being brown eyed (b) and being green eyed (b).

Explanation:

Step1: Count total offspring genotypes

Total number of genotype combinations = 4 (Bb, bb, Bb, bb)

Step2: Count brown-eyed (Bb) genotypes

Number of Bb genotypes = 2
Calculate brown-eyed percentage:
$\text{Percent brown-eyed} = \frac{2}{4} \times 100\% = 50\%$

Step3: Count green-eyed (bb) genotypes

Number of bb genotypes = 2
Calculate green-eyed percentage:
$\text{Percent green-eyed} = \frac{2}{4} \times 100\% = 50\%$

Answer:

The percent chance of offspring being brown-eyed (B) is 50%, and the percent chance of being green-eyed (b) is 50%.