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1520.00 torr = 3.00 atm + ? + 204.00 kpa

Question

1520.00 torr = 3.00 atm + ? + 204.00 kpa

Explanation:

Step1: Convert atm to torr

We know $1\ \text{atm} = 760\ \text{torr}$, so:
$3.00\ \text{atm} = 3.00 \times 760\ \text{torr} = 2280\ \text{torr}$

Step2: Convert kPa to torr

We know $1\ \text{kPa} \approx 7.50062\ \text{torr}$, so:
$204.00\ \text{kPa} = 204.00 \times 7.50062\ \text{torr} \approx 1530.13\ \text{torr}$

Step3: Rearrange to solve for unknown

Let the unknown be $x$ (in torr). Rearrange the equation:
$x = 1520.00\ \text{torr} - 2280\ \text{torr} - 1530.13\ \text{torr}$

Step4: Calculate the unknown

$x = 1520.00 - 2280 - 1530.13 = -2290.13\ \text{torr}$
(To convert back to a more standard unit, $-2290.13\ \text{torr} = \frac{-2290.13}{760}\ \text{atm} \approx -3.01\ \text{atm}$, or $-2290.13\ \text{torr} \times \frac{1\ \text{kPa}}{7.50062\ \text{torr}} \approx -305.3\ \text{kPa}$)

Answer:

The unknown value is approximately $\boldsymbol{-2290\ \text{torr}}$ (or $\boldsymbol{-3.01\ \text{atm}}$ / $\boldsymbol{-305\ \text{kPa}}$)