Question

16
factor by gcf
$39xy-26x+13y$
$13(3xy+2x-y)$
$1(13xy-26x+13y)$
$13(3xy-2x+y)$
$13xy(3-2x+y)$

Explanation:

Step1: Identify GCF of coefficients

Find GCF of 39, 26, 13: $\text{GCF}(39,26,13)=13$

Step2: Divide each term by GCF

$\frac{39xy}{13}=3xy$, $\frac{-26x}{13}=-2x$, $\frac{13y}{13}=y$

Step3: Factor out GCF

Rewrite expression with GCF factored: $13(3xy-2x+y)$

Step4: Match with options

Compare to given choices to find the match.

Answer:

13(3xy-2x+y)