Question

1. (-4, 3) and (7, 8); (9, -2) and (1, -3)

Explanation:

Assuming the problem is to find the slopes of the two lines formed by these pairs of points and compare them (or perform a related task like checking if they are parallel, perpendicular, etc.), here's the solution for finding the slopes:

Step 1: Recall the slope formula

The slope \( m \) between two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by \( m=\frac{y_2 - y_1}{x_2 - x_1} \).

Step 2: Find the slope of the line through \((-4, 3)\) and \((7, 8)\)

Let \( (x_1, y_1)=(-4, 3) \) and \( (x_2, y_2)=(7, 8) \).
Using the slope formula:
\( m_1=\frac{8 - 3}{7-(-4)}=\frac{5}{7 + 4}=\frac{5}{11} \)

Step 3: Find the slope of the line through \((9, -2)\) and \((1, -3)\)

Let \( (x_1, y_1)=(9, -2) \) and \( (x_2, y_2)=(1, -3) \).
Using the slope formula:
\( m_2=\frac{-3-(-2)}{1 - 9}=\frac{-3 + 2}{-8}=\frac{-1}{-8}=\frac{1}{8} \)

Answer:

The slopes of the lines through the given pairs of points are \( \frac{5}{11} \) (for \((-4, 3)\) and \((7, 8)\)) and \( \frac{1}{8} \) (for \((9, -2)\) and \((1, -3)\)). If the intended task was something else (like checking parallelism/perpendicularity), since \( \frac{5}{11}
eq\frac{1}{8} \) and \( \frac{5}{11}\times\frac{1}{8}=\frac{5}{88}
eq - 1 \), the lines are neither parallel nor perpendicular.